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Hybrid Inverter Pure Sine Wave Inverter
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Hybrid Inverter Pure Sine Wave Inverter

Hybrid Inverter Pure Sine Wave Inverter

FTS series :hybrid inverter pure sine wave inverter
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Product Details ofHybrid Inverter Pure Sine Wave Inverter

FTS series :hybrid inverter pure sine wave inverter

 

At any two points g and h in the conductor, the voltage is defined as the mechanical work required by the electric field force to move the unit charge from point g to point h:

where Vgh is the voltage, w is the mechanical work, q is the amount of electric charge, and dL is the microwire element.

Assume that, along the integration path, the current density J=jI is uniform and parallel to the tiny line elements:

dL=dlI; where I is the unit vector of the integration path.

Then, the voltage can be obtained:

Vgh=Jρl; where l is the path length of the integral path.

Assuming the conductor has uniform resistivity, the current density through the conductor is also uniform:

J=I/a; (the part in bold is a vector (called a vector in Taiwan) where a is the cross-sectional area of the conductor.

The voltage Vgh is abbreviated as V. Voltage is proportional to current:

V=Vgh=Iρl/a. In summary, the relationship between resistance and resistivity is

R= pl/a. Assuming that J> 0, then V> 0; to move the unit charge from point g to point h, the mechanical work that the electric field force needs to do w> 0. Therefore, the potential at point g is higher than the potential at point h, and the potential difference from point g to point h is V. From point g to point h, the voltage drop is V; from point h to point g, the voltage rise is V.


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