Pure Sine Wave Inverter 1000w-6000w

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series circuit

Assuming that n appliances are connected in series, then

Current: I total=I1=I2…=In (in a series circuit, the currents of all parts of the circuit are equal);

Voltage: U total=U1+U2…+Un (total voltage is equal to the sum of the voltages of each part);

Resistance: R total = R1+R2...+Rn (total resistance is equal to the sum of the resistances of each part).

parallel circuit

Assuming that an electrical appliances are connected in parallel, then

ammeter

Current: I total=I1+I2…+In (in a parallel circuit, the main circuit current is equal to the sum of the branch currents);

Voltage: U total=U1=U2…=Un (the voltages at both ends of each branch are equal and equal to the power supply voltage);

Resistance: (the reciprocal of the total resistance is equal to the sum of the inverses of the resistances of each part). When two electrical appliances are connected in parallel, there is the following derivation formula: .

Resistance formula derivation method

(1) series connection

From U total=U1+U2...+Un, I get I total R total=I1R1+I2R2...+InRn. Because the currents of each part of the series circuit are equal, that is, I total=I1=I2…=In, so we get: R total=R1+R2…+Rn (for example: a 3Ω resistor and a 6Ω resistor are connected in series, and the total resistance in series 9Ω).

(2) Parallel connection

From I total=I1+I2…+In, U total/R total=U1/R1+U2/R2…+Un/Rn. Because the voltage of each part of the parallel circuit is equal to the total voltage, that is, U total=U1=U2…=Un, so we get: (for example: a 3Ω resistor and a 6Ω resistor in parallel, the total resistance in parallel is 2Ω). [10]

For the part where only two resistors are connected in parallel, the following formula can be deduced: From, we know.

A conclusion can also be drawn from the above formula: the total resistance in series is greater than any one of its resistances, and the total resistance in parallel is less than any one of its resistances.

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